If Hf of CO2 is -94.05 kcal/mol, and the Hf of CO is -26.41 kcal/mol, calculate the dH for the reaction

If Hf of CO2 is -94.05 kcal/mol, and the Hf of CO is -26.41 kcal/mol, calculate the dH for the following reaction: CO + 1/2O2 —> CO2

Answer

dH = Hf(products) – Hf(reactants) = (-94.05) – (-26.41) = -67.46 kcal/mol