Hf of H2O is -57.798 kcal/mol and Hf of WO3 is -200.84 kcal/mol. Calculate dH for the reaction

Hf of H2O is -57.798 kcal/mol and Hf of WO3 is -200.84 kcal/mol. Calculate dH for the reaction
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Hf of H2O is -57.798 kcal/mol and Hf of WO3 is -200.84 kcal/mol. Calculate dH for the reaction 3H2 + WO3–> W(s)  + 3H2O

Answer

Hf (products) – Hf(reactants) = [3(-57.798) + 0] – [-200.84 + 3 * 0] = 27.45 kcal/mol